1) решить уравнениеsin 5 x=

1. sin5x=-K (3) /2; 5x=(-1) (k+1)*p/3+pn, х=(-1) (k+1)*p/15+(pn) /5,nєZ.2. К (3)*tg (a) -1=К (3)*tg (a) -tg (a) ctg (a)=tg (a)*(K (3) -ctg (a) или так: К (3)*tg (a) -1=К (3)*(sin (a) /cos (a) -1=(К (3)*sin (a) -cos (a) /cos (a)=2*(К (3) /2)*sin (a) — (1/2)*cos (a) /cos (a)=2*(cos (p/6) sin (a) -sin (p/6) cos (a) /cos (a)=2*sin (a-p/6)*(1/cos (a)