Помогите решить интегрирование по частям int sqrtx lnx dx

∫ √x ln x dx=√x=t →x=t² → dx=2t dt∫ √x ln x dx=∫ t ln (t²) (2t dt)=∫ 2t² ln (t²) dt=(t²)=u and 2t²dt=dv2t / t²) dt=(2 / t) dt=du 2 (t²⁺¹) / (2+1)=(2/3) t³=v∫ 2t² ln (t²) dt=(2/3) t³ ln (t²) — ∫ (2/3) t³ (2/ t) dt=(2/3) t³ ln (t²) — (4/3) ∫ (t³/ t) dt=(2/3) t³ ln (t²) — (4/3) ∫ t² dt=(2/3) t³ ln (t²) — (4/3) (t²⁺¹) / (2+1)+c=(2/3) t³ ln (t²) — (4/3) (1/3) t³+c=(2/3) t³ ln (t²) — (4/9) t³+c t=√x∫ √x ln x dx=(2/3) √x³ ln (√x²) — (4/9) √x³+c=(2/3) x√x ln x — (4/9) x√x+c