Вычислите пожалуйста придел функции: x² — 25 1) lim — x⇒-5 x+5 2x+x²…

im[x->0] sin (x)=x — x^3/6+lim[x->0] cos (x)=1-x^2/2+lim[x->0] tg (x)=x+1/3*x^3+lim[x->0] (tg (x) -sin (x)=(1/3+1/6)*x^3=1/2*x^3 lim[x->0] (1-cos (a*x)=1/2*a^2*x^2 lim[x->0] (tg (x) -sin (x) /x/ (1-cos (a*x)=1/a^2 2. tg (x) -sin (x)=sin (x) /cos (x)*(1-cos (x)=sin (x)*2*sin^2 (x/2) /cos (x) 1-cos (a*x)=2*sin^2 (a/2*x) ^2 lim[x->0] sin (x) /x (sin (x/2) /x/2) ^2*(a*x/2/sin (a*x/2) ^2 1/cos (x)*1/a^2=1/a^2