Заданы функции f (x)=3\2+x и g (x)=x+1\2 Найдите: 1) f (1)+g

1) f (1)=3/2+1=2,5g (3)=3+1/2=3,5f (1)+g (3)=2,5+3,5=62) g (7)=7+1/2=7,5f (7)=3/2+7=8,5g (7) -f (7)=7,5-8,5=-13) f (4)=3/2+4=5,5g (4)=4+1/2=4,5f (4)+g (4)=5,5+4,5=104) g (5)=5+1/2=5,5f (10)=3/2+10=11,5g (5) -f (10)=5,5-11,5=-6